CORRIGE DU TP 2


% exercice 1

A=[10,7,8,7;7,5,6,5;8,6,10,9;7,5,9,10]
det(A)
inv(A)
A*A
A.*A
b1=[32;23;33;31]
b2=[32.1;22.9;33.1;30.9]
A\b1
A\b2


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% exercice 2 : triangle de Pascal

n=input('dimension ? ');
C=zeros(n,n);
for i=1:n
    C(i,1)=1;
    for j=2:i
        C(i,j)=C(i-1,j-1)+C(i-1,j);
    end
end
B=C/2~=floor(C/2);
spy(B)